Sandy asks…Distance of ball after 2 s it is thrown downwards?A tennis ball is thrown down from the top of a 120m building with an initial velocity of 8m/s. What is the distance of the ball from the top of the roof 2 seconds after it was thrown?
Acceleration due to gravity is 9.8m/s^2
Please don't use a physics formula to solve this question. Use derivatives.
Show clear steps please.Nancy answers:A = dv/dt, so v = integral(a dt) = a*t + C
From the initial conditions, you know that at t = 0,
