Chris asks…If a projectile is launched from Earth with a speed equal to the escape speed, how high above the Earth's surfIf a projectile is launched from Earth with a speed equal to the escape speed, how high above the Earth's surface is it when its speed is 41% the escape speed? km Please explain using the numbers in the problem if you can since im not very good at physics. Thanks!Nancy answers:Potential energy P of gravitation field 1/R² is given by:
F(R) = -GmM / R²
P(R) = 1/m
