Donald asks…How many liters of a 10% alcohol solution must be mixed with 30 L of a 90% solution to get a 60% solution?Nancy answers:0.1x + 0.9 *30 = (30 + x)*0.6 where x = lit of 10% alcohol soln
0.1x + 27 = 18 + 0.6x
0.5x = 9
x = 9/0.5 = 90/5 = 18 litRichard asks…How many liters of a 20% alcohol solution must be mixed with 10 liters of an 80% solution to get a 40%...?solution? How can this answer be found?Nancy answers:I am assuming the question is:
"How many liters of a 20% alcohol
