Mary asks…how many liters of a 90% acid solution must be added to 6 liters of a 15% acid solution to obtain a 40% acid?solution?Nancy answers:0.90x + 0.15(6)
------------------------ = 0.40
x + 6
0.90x + 0.90
--------------------- = 0.40
x + 6
0.40(x + 6) = 0.90x + 0.90
0.40x + 2.40 = 0.90x + 0.90
-0.50x = -1.50
x = 3
The answer is 3 liters.
-----------------------------------------------------------------------------------------Betty asks…How many liters of pure water should be
