Susan asks…Please help with this chemistry question, about freezing point and molality?How many liters of ethylene glycol antifreeze (c2h6O2) would you add to your car radiator containing 15.0 L of water if you needed to protect your engine to -17.8 C? The density of ethylene glycol is 1.1 g/mL. For water, K(freezing) = 1.86 C/m.Nancy answers:17.8 = 1.86 x m
m = 9.57 = moles solute / 15.0 Kg
moles solute =143.6
Mass = 143.6 mol x 62 g/mol =8903 g
V = 8903 / 1.1 =8094 mL = 8.09 LChris
