Ken asks…Chemistry molarity question?One way to determine the amount of chloride ion in a water sample is to titrate the sample with standard AgNO3 solution to produce solid AgCl.
Ag+(aq) + Cl -(aq) AgCl(s)
If a 15.1 mL water sample requires 22.2 mL of 0.114 M AgNO3 in such a titration, what is the concentration of Cl - in the sample?Nancy answers:Ag+ + Cl^-1 --> AgCl
22.2 mL x 0.114 M = 2.53 millimoles Ag^+1 (0.00253 mole)
0.00253 mole Cl^-1 reacts with 0.00253 mole Ag^+1
2.53
