Paul asks…At the outer edge of a rotating space habitat, 130 m from its center, the rotational acceleration is g. What i?At the outer edge of a rotating space habitat, 130 m from its center, the rotational acceleration is g. What is the rotational acceleration at a distance of 65 m from the center of the habitat?Nancy answers:Find the angular velocity by
w^2R = g = 9.81 m/s^2
w^2 = 9.81/130
w = 0.2747 rad/s
and at R = 65:
a = w^2R = 0.2747^2*65 = 4.905 m/s^2 (= g/2)
(it was already
