Linda asks…0.750 g of C6H9Cl3 is mixed with 1.000 kg of AgNO3 in a flask of water. A white solid, AgCl, completely precip?C6H9Cl3 + 3AgNO3 ---> AgCl + C6H9(NO3)3Nancy answers:First what is ur Q....any how if u want how much AgCl formed
C6H9Cl3 + 3AgNO3 ---> 3 AgCl + C6H9(NO3)3.....balanced
mole of C6H9Cl3 = 0.75/molar mas = 0.75/211.5 =0.0035 mol
AgNO3 moles = 1000g/169.87=5.887 mol
total mol=5.891 mol this produce 3 mol of AgCl
mole of AgCl = 1.964 mol
mass = mol* molar mass =
